Question

Two skaters have weight in the ratio $4:5$ and are $9$ m apart, on a smooth frictionless surface,They pull on a rope stretched between them. The ratio of the distance covered by them when they meet each other will be

• A. $5:4$
• B. $4:5$
• C. $25:16$
• D. $16:25$

Answer 1

The correct option is A $5:4$

Since, the mass is inversely proportional to the distance covered.

It can be written as,

$\frac{d_1}{d_2}=\frac{m_2}{m_1}$

$\frac{d_1}{d_2}=\frac{5}{4}$

Thus, the ratio of distance covered two skaters when the meet each other will be $\frac{5}{4}$.