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Question

Two slits spaced 0.25 mm apart are placed at 0.75 m from a screen and illuminated by coherent light with a wavelength of 650 nm. The intensity at the centre of the central maximum (θ=0) is I0. The distance on the screen from the centre of central maximum to the point where the intensity has fallen to I02 is nearly

A
0.1 mm
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B
25 mm
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C
0.4 mm
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D
0.5 mm
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Solution

The correct option is D 0.5 mm
I=I0cos2(πd sinθ)λ=I02
cos(πd sinθλ)=12
we get,
x=λD4d=650×109×0.754×0.25×103=487.5×106m
=0.4875mm=0.5mm

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