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Question

Two small dipoles of dipole moment P1 and P2 are placed as shown in figure. k=14πϵo

A
Torque on P2 due to P1 is zero
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B
Torque on P1 due to P2 is 2kP1P2r3
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C
Torque on P1 due to P2 is zero
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D
Force on P1 due to P2 is zero
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Solution

The correct option is D Force on P1 due to P2 is zero

E1 is field at P2 due to P1
E2 is field at P1 due to P2
E1=kP1r3 and E2=2kP2r3
τ=P×E
So |τ|=P1E2 sin 90o=2kP1P2r3
Force F=Ur where U=PE cos θ
here θ=π2, U = 0 and F = 0.

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