Two small identical spheres having charges $+ 10 μ C$ and $- 90 μ C$ attract each other with a force of $F$ Newton. If they are Kept in contact and then separated by the same distance, The new force between them is:

F / 6

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16 / F

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16 F / 9

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9 F

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Solution

The correct option is C $16 F / 9$
Initial force,
$F = k \frac{900 \times 10^{- 12}}{r^{2}} N$
After keeping in contact, due to induction;

$q_{A} = - 40 μ C$

$q_{B} = - 40 μ C$

So, new force;
$F^{'} = k \frac{1600 \times 10^{- 12}}{r^{2}} N$

$\frac{F^{'}}{F} = \frac{1600}{900}$

$F^{'} = \frac{16}{9} F$

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