Two small metal balls of different mass $m_{1}$ and $m_{2}$ are connected by strings of equal length to a fixed point. When the balls are given charges, the angles that the two strings make with the vertical are $30^{o}$ and $60^{o}$ , respectively. The ratio $m_{1} / m_{2}$ is close to :

1.7

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3.0

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0.58

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2.0

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Solution

The correct option is C $1.7$
$M_{2} g s i n 60^{o} = F c o s 45^{o}$
$M_{1} g s i n 30^{o} = F c o s 45^{o}$
$M_{1} g s i n 30^{o} = M_{2} g s i n 60^{o}$
$\frac{M_{1}}{M_{2}} = \frac{s i n 60^{0}}{s i n 30^{0}}$
$\frac{M_{1}}{M_{2}} = 1.73$

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Two small metal balls of different mass m1 and m2 are connected by strings of equal length to a fixed point. When the balls are given charges, the angles that the two strings make with the vertical are 30o and 60o, respectively. The ratio m1/m2 is close to :

The correct option is C 1.7M2gsin60o=Fcos45oM1gsin30o=Fcos45oM1gsin30o=M2gsin60oM1M2=sin600sin300M1M2=1.73

Two small metal balls of different mass $m_{1}$ and $m_{2}$ are connected by strings of equal length to a fixed point. When the balls are given charges, the angles that the two strings make with the vertical are $30^{o}$ and $60^{o}$ , respectively. The ratio $m_{1} / m_{2}$ is close to :

The correct option is C $1.7$
$M_{2} g s i n 60^{o} = F c o s 45^{o}$
$M_{1} g s i n 30^{o} = F c o s 45^{o}$
$M_{1} g s i n 30^{o} = M_{2} g s i n 60^{o}$
$\frac{M_{1}}{M_{2}} = \frac{s i n 60^{0}}{s i n 30^{0}}$
$\frac{M_{1}}{M_{2}} = 1.73$