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Question

Two small objects X and Y are permanently separated by a distance 1 cm. Object X has a charge of +1.0μC and object Y has a charge of 1.0μC. A certain number of electrons are removed from X and put onto Y to make the electrostatic force between the two objects an attractive force whose magnitude is 360 N. Number of electrons removed is :


A
8.4×1013
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B
6.25×1012
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C
4.2×1011
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D
3.5×1010
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Solution

The correct option is C 6.25×1012
New attractive force is -360 N.
360 N=K(q1)(q2)r2
K=9×109, r=102 m
360 N=K(1×106+ne)((1×106)ne)(1×102)2
360×1049×109=(1×106+ne)2
41012=(1×106+ne)2
2×106=1×106+ne.
ne=1×106
n=1×106=1×10616×1019=625×1012
63412_10839_ans_28bd6260ef3e449bb992feff4cf762fc.png

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