Question

Two small spheres each having the charge +Q are suspended by insulating threads of length L from a hook. This arrangement is taken in space where there is no gravitational effect, then the angle between the two suspensions and the tension in each will be

• A. ${180}^{\circ },\frac{1}{4\pi {\epsilon }_0}\frac{Q^2}{(2L{)}^2}$
• B. ${90}^{\circ },\frac{1}{4\pi {\epsilon }_0}\frac{Q^2}{L^2}$
• C. ${180}^{\circ },\frac{1}{4\pi {\epsilon }_0}\frac{Q^2}{2L^2}$
• D. ${180}^{\circ },\frac{1}{4\pi {\epsilon }_0}\frac{Q^2}{L^2}$

Answer 1

The correct option is A ${180}^{\circ },\frac{1}{4\pi {\epsilon }_0}\frac{Q^2}{(2L{)}^2}$

The position of the balls in the space will become as shown below

Thus angle $\theta ={180}^{\circ }$ and Force = $\frac{1}{4\pi {\epsilon }_0}.\frac{Q^2}{(2L{)}^2}$