You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Coulomb's Law - Mathematical Form

Two small sph...

Question

Two small spheres with masses $M_{1}$ and $M_{2}$ hang on weightless, insulating threads with lengths $L_{1}$ and $L_{2}$ . The two spheres carry a charge of $Q_{1}$ and $Q_{2}$ respectively. The spheres hang such that they are level with one another and the threads are inclined to the vertical at angles $θ_{1}$ and $θ_{2}$ . Which of the following conditions is required if $θ_{1} = θ_{2}$ .

M_{1} = M_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

| Q_{1} | = | Q_{2} |

No worries! We‘ve got your back. Try BYJU‘S free classes today!

L_{1} = L_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $M_{1} = M_{2}$
$θ_{1} = θ_{2}$ , if their masses are the same because the force of repulsion due to charges is the same. The force Mg $sin θ$ opposes the force of repulsion. Even if $Q_{1}$ and $Q_{2}$ are different, the force of repulsion is the same for both as they are mutual.

Suggest Corrections

Similar questions

Q. Two small spheres with mass

m_{1}

and

m_{2}

hang from massless insulating threads of length

l_{1}

and

l_{2}

. The two spheres carry charges

q_{1}

and

q_{2}

respectively. The spheres hang such that they are on the same horizontal level and the threads are inclined to the vertical at angles

θ_{1}

and

θ_{2}

. Which of the conditions is required if

θ_{1} = θ_{2}

Q. Two small spheres of masses

M_{1}

and

M_{2}

are suspended by weightless insulating threads of lengths

L_{1}

and

L_{2}

, the spheres carry charges

Q_{1}

and

Q_{2}

respectively. The spheres are suspended such that they are in level with another and the threads are inclined to the vertical at angles of

θ_{1}

and

θ_{2}

as shown, which one of the following conditions is essential, if

θ_{1} = θ_{2} :

Q. Two small spheres have mass

m_{1}

and

m_{2}

and hanging from massless insulating threads of lengths

l_{1}

and

l_{2}

. Two spheres carry charges

q_{1}

and

q_{2}

respectively. The spheres hang such that they are on the same horizontal level and the threads are inclined to the vertical at angle

θ_{1}

and

θ_{2}

respectively. If

F_{1} = F_{2}

, then:

Two positively charged spheres of masses $m_{1}$ and $m_{2}$ , are suspended from a common point at the ceiling by identical insulating massless strings of length l. Charges on the two spheres are $q_{1}$ and $q_{2}$ , respectively. At equilibrium both strings make the same angle $θ$ with the vertical. Then

Join BYJU'S Learning Program

The correct option is A M1=M2θ1=θ2, if their masses are the same because the force of repulsion due to charges is the same. The force Mg sinθ opposes the force of repulsion. Even if Q1 and Q2 are different, the force of repulsion is the same for both as they are mutual.