Two soap bubbles are blown. In first soap bubble excess pressure is 4 times of the second soap bubble. The ratio of the radii of the first and second soap bubble is:

1:4

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1:2

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2 :1

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4:1

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Solution

The correct option is C 1:4
Excess pressure = $Δ P = \frac{4 T}{R}$
According to problem, $\frac{Δ P_{A}}{Δ P_{B}} = 4 = \frac{4 T / R_{A}}{4 T / R_{B}} = \frac{R_{B}}{R_{A}}$
Therefore, $\frac{R_{A}}{R_{B}} = \frac{1}{4}$

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Two soap bubbles are blown. In first soap bubble excess pressure is 4 times of the second soap bubble. The ratio of the radii of the first and second soap bubble is:

The correct option is C 1:4Excess pressure = ΔP=4TRAccording to problem, ΔPAΔPB=4=4T/RA4T/RB=RBRATherefore, RARB=14

The correct option is C 1:4
Excess pressure = $Δ P = \frac{4 T}{R}$
According to problem, $\frac{Δ P_{A}}{Δ P_{B}} = 4 = \frac{4 T / R_{A}}{4 T / R_{B}} = \frac{R_{B}}{R_{A}}$
Therefore, $\frac{R_{A}}{R_{B}} = \frac{1}{4}$