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Standard XII

Physics

Gravitational Field

Two soap bubb...

Question

Two soap bubbles combine under isothermal conditions to form a single soap bubble. If in the process, the change in volume is $V$ and change in area is $S$ , then $(P$ at atmospheric pressure).

P V + T S = 0

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4 P V + 3 T S = 0

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3 P V + 4 T S = 0

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3 P V + T S = 0

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Solution

The correct option is C $3 P V + 4 T S = 0$

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Similar questions

Two soap bubbles combine under isothermal conditions to form a single soap bubble. If in the process, the change in volume is

V

and change in area is

S

, then

(

P

is atmospheric pressure and

T

is the ambient temperature).

Q. Two spherical soap bubble coalesce. If

V

is the consequent change in volume of the contained air and

S

the change in total surface area, show that

3 P V + 4 S T = 0

where

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is the surface tension of soap bubble and

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is atmospheric pressure.

Q. Two soaps bubbles (surface tension

T

) coalesce to form a big bubble under isothermal condition. If in this process the change in volume be

V

and the surface area be

S

, then the correct relation is (

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Q. Two soap bubbles of radii

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and

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combine under isothermal conditions to form a single bubble of radius

c

without any leakage of air. If

P_{0} =

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T =

surface tension of soap solution, show that

P_{0} = \frac{4 T (a^{2} + b^{2} - c^{2})}{c^{3} - a^{3} - b^{3}}

Q. Two soap bubbles combine to form a single bubble. In this process, the change in volume and surface area are

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and

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respectively. If

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is the surface tension of the soap solution, then which of the following relation is true?

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Two soap bubbles combine under isothermal conditions to form a single soap bubble. If in the process, the change in volume is V and change in area is S, then (P at atmospheric pressure).

The correct option is C 3PV+4TS=0

Two soap bubbles combine under isothermal conditions to form a single soap bubble. If in the process, the change in volume is $V$ and change in area is $S$ , then $(P$ at atmospheric pressure).

The correct option is C $3 P V + 4 T S = 0$