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Excess Pressure in Bubbles

Two soap bubb...

Question

Two soap bubbles of different radii $R_{1}$ , and $R_{2} (< R)$ coalesee to form an interface of radius R, The correct value of R is

R = R_{1} - R_{2}

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R = \frac{R_{1} + R_{2}}{2}

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\frac{1}{R} = \frac{1}{R_{2}} - \frac{1}{R_{1}}

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\frac{1}{R} = \frac{1}{R_{2}} + \frac{1}{R_{1}}

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Solution

The correct option is B $\frac{1}{R} = \frac{1}{R_{2}} - \frac{1}{R_{1}}$
$(p_{2} - p_{1}) = \frac{4 T}{R}$
where R=radius of common surface
$∴$ $\frac{4 T}{R_{2}} - \frac{4 T}{R_{1}} = \frac{4 T}{R}$
or $\frac{1}{R} = \frac{1}{R_{2}} - \frac{1}{R_{1}}$

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Two soap bubbles of different radii R1, and R2(<R) coalesee to form an interface of radius R, The correct value of R is

The correct option is B 1R=1R2−1R1(p2−p1)=4TRwhere R=radius of common surface∴ 4TR2−4TR1=4TRor 1R=1R2−1R1

Two soap bubbles of different radii $R_{1}$ , and $R_{2} (< R)$ coalesee to form an interface of radius R, The correct value of R is

The correct option is B $\frac{1}{R} = \frac{1}{R_{2}} - \frac{1}{R_{1}}$
$(p_{2} - p_{1}) = \frac{4 T}{R}$
where R=radius of common surface
$∴$ $\frac{4 T}{R_{2}} - \frac{4 T}{R_{1}} = \frac{4 T}{R}$
or $\frac{1}{R} = \frac{1}{R_{2}} - \frac{1}{R_{1}}$