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Surface Tension

Two soap bubb...

Question

Two soap bubbles of radii 4 cm and 5 cm coalesce to form a common surface. The radius of curvature of common surface will be :-

20 cm

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10 cm

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1.25 cm

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2.22 cm

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Solution

The correct option is A 20 cm

$Tension remain same$
$\frac{4 T}{R} = \frac{4 T}{R_{1}} - \frac{4 T}{R_{2}}$
$\frac{1}{R} = \frac{1}{4} - \frac{1}{5} \Rightarrow R = 20 c m$
$Answer: (A)$

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Two soap bubbles of radii 4 cm and 5 cm coalesce to form a common surface. The radius of curvature of common surface will be :-

The correct option is A 20 cm Tension remain same 4TR=4TR1−4TR21R=14−15⇒R=20 cm Answer: (A)

The correct option is A 20 cm

$Tension remain same$
$\frac{4 T}{R} = \frac{4 T}{R_{1}} - \frac{4 T}{R_{2}}$
$\frac{1}{R} = \frac{1}{4} - \frac{1}{5} \Rightarrow R = 20 c m$
$Answer: (A)$