Two soap bubbles of radii $r_{1}$ and $r_{2}$ equal to $4 c m$ and $5 c m$ are touching each other over a common surface $S_{1} S_{2}$ (shown in figure). Its radius of surface $S_{1} S_{2}$ will be:

4 c m

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20 c m

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5 c m

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4.5 c m

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Solution

The correct option is B $20 c m$
$2 T / r + 2 T / R = 2 T / r^{'}$
$1 / r + 1 / R = 1 / r^{'}$
$1 / 5 + 1 / R = 1 / 4$
$1 / R = 1 / 4 - 1 / 5 = 1 / 20$
$R = 20 c m$

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