You visited us 1 times! Enjoying our articles? Unlock Full Access!

Concept of Force

Two soap bubb...

Question

Two soap bubbles of radii $r_{1} a n d r_{2}$ equal to 4cm and 5cm are touching each other over a common surface $S_{1} S_{2}$ (shown in figure). The radius of common surface will be

4 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.5 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 20 cm
Radius of curvature of common surface of double bubble $r = \frac{r_{2} r_{1}}{r_{2} - r_{1}} = \frac{5 \times 4}{5 - 4} = 20 c m$

Suggest Corrections

Similar questions

Q. Two soap bubbles of radii 4 cm and 5 cm are touching each other over a common surface

S_{1} S_{2}

(shown in figure), its radius will be

Two soap bubbles of radii $r_{1}$ and $r_{2}$ equal to 4 cm and 5 cm are touching each other over a common surface $s_{1} s_{2}$ (shown in figure). Its radius will be

Q. Two soap bubbles of radii

r_{1}

and

r_{2}

equal to

4 c m

and

5 c m

are touching each other over a common surface

S_{1} S_{2}

(shown in figure). Its radius of surface

S_{1} S_{2}

will be:

Q. Two soap bubbles of radii

4 cm

and

5 cm

are touching each other over a common surface

S_{1} S_{2}

(shown in figure). Then, radius of the common surface will be

Q. Two soap bubbles of radii

r_{1}

and

r_{2}

equal to 4cm and 5 cm are touching each other over a common surface

S_{1} S_{2}

(shown in figure). Its radius will be :

Join BYJU'S Learning Program

Two soap bubbles of radii r1 and r2 equal to 4cm and 5cm are touching each other over a common surface S1S2 (shown in figure). The radius of common surface will be

The correct option is B 20 cmRadius of curvature of common surface of double bubble r=r2r1r2−r1=5×45−4=20cm

Two soap bubbles of radii $r_{1} a n d r_{2}$ equal to 4cm and 5cm are touching each other over a common surface $S_{1} S_{2}$ (shown in figure). The radius of common surface will be

The correct option is B 20 cm
Radius of curvature of common surface of double bubble $r = \frac{r_{2} r_{1}}{r_{2} - r_{1}} = \frac{5 \times 4}{5 - 4} = 20 c m$