Two soap bubbles of radii R and r come in contact. R is greater than r. Radius of curvature of common surface is

\frac{R r}{R - r}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{R r}{r + R}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{(R + r) R}{r}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{(R - r) R}{r}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{R r}{R - r}$

$P_{r} = \frac{4 T}{r} a n d P_{R} = \frac{4 T}{R}$
$∴ P_{r} - P_{R} = \frac{4 T}{r^{'}}$
$\Rightarrow \frac{4 T}{r} - \frac{4 T}{R} = \frac{4 T}{r^{'}}$
$\frac{1}{r^{'}} = \frac{R - r}{R r}$
$\Rightarrow r^{'} = \frac{R r}{R - r}$ .

Suggest Corrections

Similar questions

Q. Two soap bubbles with radii

r_{1}

and

r_{2}

(r_{1} > r_{2})

come in contact. Their common surface has a radius of curvature

r =

Q. A hollow metal sphere of radius

R

is uniformly charged. The electric field due to the sphere at a distance

r

from the centre

Q. Two soap bubbles with radii

r_{1}

and

r_{2} (r_{1} < r_{2})

come in contact. Their common surface has a radius of curvature

r

equal to

A round seeded plant ( R ) is dominant to a wrinkled seeded plant ( r). What parental genotypes will produce offspring that are 50% homozygous dominant and 50% heterozygous dominant ?

Q. In shorthorn cattle, genes for red (R) and white (r) coat colour occur. Cross between red (RR) and white (rr) produces roan (Rr). This is an example of

Join BYJU'S Learning Program

Two soap bubbles of radii R and r come in contact. R is greater than r. Radius of curvature of common surface is

The correct option is A RrR−r Pr=4TrandPR=4TR ∴Pr−PR=4Tr′ ⇒4Tr−4TR=4Tr′ 1r′=R−rRr ⇒r′=RrR−r.

The correct option is A $\frac{R r}{R - r}$

$P_{r} = \frac{4 T}{r} a n d P_{R} = \frac{4 T}{R}$
$∴ P_{r} - P_{R} = \frac{4 T}{r^{'}}$
$\Rightarrow \frac{4 T}{r} - \frac{4 T}{R} = \frac{4 T}{r^{'}}$
$\frac{1}{r^{'}} = \frac{R - r}{R r}$
$\Rightarrow r^{'} = \frac{R r}{R - r}$ .