Question

Two solenoids of same cross-sectional area have their lengths and number of turns in ratio of $1:2$. The ratio of self-inductance of two solenoids is?

• A. $1:1$
• B. $1:2$
• C. $2:1$
• D. $1:4$

Answer 1

The correct option is A $1:1$

self-inductance is directly proportional to the square of its number of turns

$\frac{L_1}{L_2}$ = $(\frac{N_1}{N_2}{)}^2$

$\frac{L_2}{L_1}=\frac{1}{4}$