Two solid bodies X and Y having same volume floats in a liquid. It is observed that X floats with 50% of its volume immersed in liquid and Y floats with 25% of its volume above the liquid level. The ratio of density of X to Y is
A
3:2
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B
2:3
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C
2:5
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D
5:2
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Solution
The correct option is B2:3 Let ρ be the density of the liquid. In equilibrium, Bouyant force on body X by water, Fbx=ρgV2 This will balance the weight of body X. ∴mxg=ρxgV=Fbx=ρgV2 ⇒ρx=ρ2 ...........(1) Similarly, Bouyant force on body Y by water, Fby=3ρgV4 This will balance the weight of body Y. ∴myg=ρygV=Fby=3ρgV4 ⇒ρy=3ρ4 ............(2) So, ρxρy=23=2:3 [ from (1) and (2) ]