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Non Contact Collision

Two solid rub...

Question

Two solid rubber balls $A$ and $B$ having masses $200$ grams and $400$ grams are moving in opposite directions with velocity of $A$ equal to $0.3 m / s$ . After collision the two balls come to rest, then the velocity of $B$ is

0.15 m / s

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1.5 m / s

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- 0.15 m / s

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None

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Solution

The correct option is B $- 0.15 m / s$
Initial linear momentum of system $= m_{A}_{A} + m_{B}_{B}$
$= 0.2 \times 0.3 + 0.4 \times V_{B}$
Finally both balls come to rest.
Finally linear momentum $= 0$
By the law of conservation of linear momentum.
$0.2 \times 0.3 + 0.4 \times V_{B} = 0$
$V_{B} = - \frac{0.2 \times 0.3}{0.4} = - 0.15 m / s$

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Two solid rubber balls A and B having masses 200 grams and 400 grams are moving in opposite directions with velocity of A equal to 0.3m/s. After collision the two balls come to rest, then the velocity of B is

The correct option is B −0.15m/sInitial linear momentum of system =mA¯VA+mB¯VB =0.2×0.3+0.4×VBFinally both balls come to rest.Finally linear momentum =0By the law of conservation of linear momentum.0.2×0.3+0.4×VB=0VB=−0.2×0.30.4=−0.15m/s

Two solid rubber balls $A$ and $B$ having masses $200$ grams and $400$ grams are moving in opposite directions with velocity of $A$ equal to $0.3 m / s$ . After collision the two balls come to rest, then the velocity of $B$ is