Two solid spheres have equal mass and have radius in the ratio of 1 : 3. The ratio of their densities is

9 : 1

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1 : 9

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1 : 27

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27 : 1

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Solution

The correct option is D
27 : 1
$V o l u m e o f a s p h e r e i s g i v e n b y (4 / 3) {πr}^{3}$
$\frac{D_{1}}{D_{2}} = \frac{\frac{m}{V_{1}}}{\frac{m}{V_{2}}} = \frac{V_{2}}{V_{1}} = \frac{27}{1} = 27 : 1$
Thus, the ratio of densities of solid spheres = 27 : 1

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Two solid spheres have equal mass and have radius in the ratio of 1 : 3. The ratio of their densities is

The correct option is D 27 : 1 Volume of a sphere is given by (4/3)πr3 D1D2= m/V1m/V2=V2V1=271= 27 : 1 Thus, the ratio of densities of solid spheres = 27 : 1

The correct option is D
27 : 1
$V o l u m e o f a s p h e r e i s g i v e n b y (4 / 3) {πr}^{3}$
$\frac{D_{1}}{D_{2}} = \frac{\frac{m}{V_{1}}}{\frac{m}{V_{2}}} = \frac{V_{2}}{V_{1}} = \frac{27}{1} = 27 : 1$
Thus, the ratio of densities of solid spheres = 27 : 1