Two solids A and B float in water. It is observed that A floats with half its volume immersed and B floats with $2 / 3$ of its volume immersed. Compare the densities of A and B:

4 : 3

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2 : 3

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3 : 4

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1 : 1

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Solution

The correct option is C $3 : 4$
Given that $m_{1} = V_{1} / 2 \times d ⟹ d_{1} = d / 2$
and $m_{2} = 2 V_{2} / 3 \times d ⟹ d_{2} = 2 d / 3$
$∴ d_{1} : d_{2} = 3 : 4$

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Two solids A and B float in water. It is observed that A floats with half its volume immersed and B floats with 2/3 of its volume immersed. Compare the densities of A and B:

The correct option is C 3:4Given that m1=V1/2×d⟹d1=d/2and m2=2V2/3×d⟹d2=2d/3∴d1:d2=3:4

Two solids A and B float in water. It is observed that A floats with half its volume immersed and B floats with $2 / 3$ of its volume immersed. Compare the densities of A and B:

The correct option is C $3 : 4$
Given that $m_{1} = V_{1} / 2 \times d ⟹ d_{1} = d / 2$
and $m_{2} = 2 V_{2} / 3 \times d ⟹ d_{2} = 2 d / 3$
$∴ d_{1} : d_{2} = 3 : 4$