Two solutions...

Question

Two solutions of $K N O_{3}$ and $C H_{3} C O O H$ are prepared separately having the same molar concentration.
The correct relationship between the osmotic pressures is

P_{2} > P_{1}

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P_{1} = P_{2}

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P_{1} > P_{2}

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\frac{P_{1}}{P_{1} + P_{2}} = \frac{P_{2}}{P_{1} + P_{2}}

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Solution

The correct option is C $P_{1} > P_{2}$
$K N O_{3}$ is 100% ionized while $C H_{3} C O O H$ is a weak electrolyte.

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0.1 M NaCl and 0.1 M CH₃COOH are kept in separate containers. If their osmotic pressures Are P₁ and P₂ respectively then the correct statement is:

(P_{1})

(P_{2})

(P_{3})

K N O_{3}

C H_{3} C O O H

P_{1}

P_{2}

P_{1}, P_{2}

P_{3}

K N O_{3}

C H_{3} C O O H

0.1 M

P_{1}

P_{2}