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Standard XII

Physics

The Effect of Path Difference

Two sound spe...

Question

Two sound speakers are driven in phase by an audio amplifier at frequency $600 H z$ . The speed of sound is $340 m / s$ . The speakers are on the $y$ -axis, one at $y = + 1.0 m$ and the other at $y = - 1.0 m$ . A listener begins at $y = 0$ and walks along a line parallel to the $y$ -axis at a very large distance $x$ away. How many maxima can she possibly hear if she keeps walking in the same direction ?

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Solution

The path difference is $\sqrt{x^{2} + 1} - x$
So, maxima will be at $△ x = 0$ that means on $x - a x i s$ .
and $△ x = 2 λ / 2 = λ = \frac{v}{f} = \frac{340}{600} = 0.56 m$
After that $x$ will be negative So, she will here $2$ maxima.

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The path difference is √x2+1−xSo, maxima will be at △x=0 that means on x−axis.and △x=2λ/2=λ=vf=340600=0.56mAfter that x will be negative So, she will here 2 maxima.

The path difference is $\sqrt{x^{2} + 1} - x$
So, maxima will be at $△ x = 0$ that means on $x - a x i s$ .
and $△ x = 2 λ / 2 = λ = \frac{v}{f} = \frac{340}{600} = 0.56 m$
After that $x$ will be negative So, she will here $2$ maxima.