Question

Two sound waves having a phase difference of ${60}^{\circ }$ have a path difference of

• A. $2\lambda$
• B. $\lambda /2$
• C. $\lambda /6$
• D. $\lambda /3$

Answer 1

The correct option is C $\lambda /6$

Phase difference $\delta ={60}^o=60\times \frac{\pi }{180}$ radian

$\delta =\frac{\pi }{3}$ radian

Let path difference be $\Delta x$

Using $\delta =\frac{2\pi }{\lambda }\times \Delta x$

$\frac{\pi }{3}=\frac{2\pi }{\lambda }\times \Delta x⟹\Delta x=\frac{\lambda }{6}$