Two sound waves of amplitudes 3 cm, 5 cm, travelling in the same direction superpose with each other to produce beats. If $I$ is minimum intensity of sound, in these beats the maximum intensity of sound is

4 I

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9 I

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16 I

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25 I

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Solution

The correct option is D $16 I$
Given : $I_{m i n} = I$

$\frac{I m a x}{I m i n} = \frac{(A_{1} + A_{2})^{2}}{(A_{1} - A_{2})^{2}} = \frac{(5 + 3)^{2}}{(5 - 3)^{2}} = \frac{64}{4} = \frac{16}{1}$

$s o, I_{m a x} = 16 I_{m i n}$ $= 16 I$

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Two sound waves of amplitudes 3 cm, 5 cm, travelling in the same direction superpose with each other to produce beats. If I is minimum intensity of sound, in these beats the maximum intensity of sound is

The correct option is D 16IGiven :Imin=IImaxImin=(A1+A2)2(A1−A2)2=(5+3)2(5−3)2=644=161so,Imax=16Imin=16I

Two sound waves of amplitudes 3 cm, 5 cm, travelling in the same direction superpose with each other to produce beats. If $I$ is minimum intensity of sound, in these beats the maximum intensity of sound is

The correct option is D $16 I$
Given : $I_{m i n} = I$

$\frac{I m a x}{I m i n} = \frac{(A_{1} + A_{2})^{2}}{(A_{1} - A_{2})^{2}} = \frac{(5 + 3)^{2}}{(5 - 3)^{2}} = \frac{64}{4} = \frac{16}{1}$

$s o, I_{m a x} = 16 I_{m i n}$ $= 16 I$