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Question

Two sound waves with wavelengths 5.0 m and 5.5 m respectively, each propagates in a gas with velocity 330 m/s. Number of beats heard per second is

A
6
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B
12
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C
0
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D
1
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Solution

The correct option is A 6
We know that,
Frequency =velocitywavelength
Frequency of first wave is
v1=vλ1=3305=66 Hz and
Frequency of second wave is
v2=vλ2=3305.5=60 Hz
Number of beats heard per second =v1v2
=6660=6 Hz.
Hence, the correct answer is option (a).

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