Two spheres A and B of radius 4cm and 6cm are given charges of 80 - c and 40 - c respectively- If they are connected by a fine wire- the amount of charge flowing on of the other is-

Two identical air capacitors A and B of the parallel plate type are charged to the same potential and connected in parallel (+ to +). Now a dielectric is inserted between the plates of A, then

A conductor A of capacity $4 μ F$ has a charge $20 μ C$ and another condenser B of capacity $10 μ F$ has a charge $40 μ C$ . If they are connected parallel, then:

Join BYJU'S Learning Program

Two spheres A and B of radius 4cm and 6cm are given charges of 80μc and 40μc respectively. If they are connected by a fine wire, the amount of charge flowing on of the other is:

The correct option is D 32μc from A to Bq∝1r q1r1=q2r2⇒80μC×4=q2(6+4)⇒q2=8×401032μC from A to B.

Two spheres $A$ and $B$ of radius $4 c m$ and $6 c m$ are given charges of $80 μ c$ and $40 μ c$ respectively. If they are connected by a fine wire, the amount of charge flowing on of the other is:

The correct option is D $32 μ c$ from $A$ to $B$
$q \propto \frac{1}{r}$ $q_{1} r_{1} = q_{2} r_{2}$
$\Rightarrow 80 μ C \times 4 = q_{2} (6 + 4)$
$\Rightarrow q_{2} = \frac{8 \times 40}{10} 32 μ C$ from A to B.