CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
72
You visited us 72 times! Enjoying our articles? Unlock Full Access!
Question

Two spheres P and Q of equal radii have densities ρ1 and ρ2 repectively. The spheres are connected by a massless string and placed in liquids L1 and L2 of densities σ1 and σ2 and viscosities η1 and η2 respectively. They float in equilibrium with the sphere P in L1 and Q in L2 and the string being taut (see figure). If sphere P alone in L2 has terminal velocity VP and Q alone in L1 has terminal velocity VQ,
(Terminal velocity of a sphere having radius r and density ρ thrown in a liquid having density σ and viscoscity η is given by =2r29η(ρσ)). Then which of the following are correct ?

A
VPVQ=η1η2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
VPVQ=η2η1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
VP.VQ>0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
VP.VQ<0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A VPVQ=η1η2
D VP.VQ<0
Free body diagram of P and Q when they are connected by string

For P: σ1V=ρ1V+T ...(i)
For Q: T+σ2V=ρ2V ...(ii)
Adding equations (i) and (ii)
σ1ρ2=ρ1σ2 ..(iii)
If the sphere P alone in L2
Terminal velocity of P, VP=2r29η2(ρ1σ2)


If the sphere Q alone in L1
Terminal velocity of Q, VQ=2r29η1(ρ2σ1)

VPVQ=η1η2
VPVQ=η1η2 and VP.VQ<0
as if ρ1σ2>0
ρ2σ1<0




flag
Suggest Corrections
thumbs-up
9
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Simple Harmonic Oscillation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon