Two spherical balls each of mass $1 k g$ are placed $1 c m$ apart. The gravitational force of attraction between them is

6.67 \times 10^{- 7}

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6.67 \times 10^{- 4}

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6.67 \times 10^{- 2}

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6.67 \times 10^{- 9}

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Solution

The correct option is C $6.67 \times 10^{- 7}$ N
The gravitational force of attraction is given by:
$F = \frac{G m_{1} m_{2}}{r^{2}}$
Here $m_{1} = m_{2} = 1 k g$ and $r = 1$ cm $= 0.01 m$
$F = \frac{6.67 \times 10^{- 11} \times 1^{2}}{(0.01)^{2}}$
$⟹ F = 6.67 \times 10^{- 7} N$

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Two spherical balls each of mass 1kg are placed 1cm apart. The gravitational force of attraction between them is

The correct option is C 6.67×10−7 NThe gravitational force of attraction is given by:F=Gm1m2r2Here m1=m2=1 kg and r=1 cm =0.01 mF=6.67×10−11×12(0.01)2⟹F=6.67×10−7N

Two spherical balls each of mass $1 k g$ are placed $1 c m$ apart. The gravitational force of attraction between them is

The correct option is C $6.67 \times 10^{- 7}$ N
The gravitational force of attraction is given by:
$F = \frac{G m_{1} m_{2}}{r^{2}}$
Here $m_{1} = m_{2} = 1 k g$ and $r = 1$ cm $= 0.01 m$
$F = \frac{6.67 \times 10^{- 11} \times 1^{2}}{(0.01)^{2}}$
$⟹ F = 6.67 \times 10^{- 7} N$