Two spherical balls of mass 10 kg each are placed 10 cm apart. Find the gravitional force of attraction between them.

Open in App

Solution

Gravitatonal force of attraction,
$F = \frac{G M m}{r^{2}} = \frac{6.67 \times 10^{- 11} \times 10 \times 10}{(0.1)^{2}} = 6.67 \times 10^{- 1} N$

Suggest Corrections

Similar questions

Q. Two spherical balls of mass 10 kg each are placed 10 cm apart. Find the gravitational force of attraction between them.

Q. Two spherical balls each of mass

1 k g

are placed

1 c m

apart. The gravitational force of attraction between them is

Two spherical balls of mass 10 kg each are placed with their centers 10 cm apart. Find the gravitational force of attraction between them. Take $G = 6.67 \times 10^{- 11} N m^{2} k g^{- 2}$

Q. Two objects of mass

M_{1}

and

M_{2}

are kept distance ‘2d’ apart. Find the expression for the gravitational force of attraction between them.

Q. Two balls, each of radius

R

, equal mass and density are placed in contact, then the force of gravitation between them is proportional to

Join BYJU'S Learning Program

Two spherical balls of mass 10 kg each are placed 10 cm apart. Find the gravitional force of attraction between them.

Gravitatonal force of attraction, F=GMmr2=6.67×10−11×10×10(0.1)2=6.67×10−1N

Gravitatonal force of attraction,
$F = \frac{G M m}{r^{2}} = \frac{6.67 \times 10^{- 11} \times 10 \times 10}{(0.1)^{2}} = 6.67 \times 10^{- 1} N$