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Question

# Two spherical conductors A and B of radii 1 mm and 2 mm are separated by a distance of 5 cm and are uniformly charged. If the spheres are connected by a conducting wire then in equilibrium condition, the ratio of the magnitude of the electric fields at the surface of spheres A and B is :

A
1 : 4
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B
4 : 1
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C
1 : 2
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D
2 : 1
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Solution

## The correct option is D 2 : 1Electric field at the surface of sphere of radius R is E=kQ/R2When two spherical conductors are connected by wire, the charge will flow from higher potential to lower potential till they will get same potential i.e equilibrium. Thus, VA=VB or kQA/RA=kQB/RB Thus, EAEB=RBRA=21so, option D

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