Two particles of equal masses are revolving in circular paths of radii $r_{1} a n d r_{2}$ respectively with the same speed. The ratio of their centripetal forces is

Q. Two concentric spherical shells have masses

M_{1}

and

M_{2}

and radii

R_{1}

and

R_{2}

(R_{1} < R_{2})

. What is the force exerted by this system on a particle of mass

m

if it is at a distance

\frac{(R_{1} + R_{2})}{2}

from the centre?

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Two spherical nuclei have mass numbers 216 and 64 with their radii R1 and R2 respectively.The ratio, R1R2 is equal to

The correct option is A 3 : 2The relation between radius (R) of nuclei and mass number (A) is given by R=R0A1/3 where R0= empirical constant. Thus, R1R2=A1/31A1/32=(216)1/3(64)1/3=6/4=3/2

Two spherical nuclei have mass numbers 216 and 64 with their radii $R_{1}$ and $R_{2}$ respectively.
The ratio, $\frac{R_{1}}{R_{2}}$ is equal to

The correct option is A 3 : 2
The relation between radius (R) of nuclei and mass number (A) is given by $R = R_{0} A^{1 / 3}$ where $R_{0} =$ empirical constant.
Thus, $\frac{R_{1}}{R_{2}} = \frac{A_{1}^{1 / 3}}{A_{2}^{1 / 3}} = \frac{(216)^{1 / 3}}{(64)^{1 / 3}} = 6 / 4 = 3 / 2$