wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two spring of equal lengths and equal cross sectional areas are made of materials whose Young's modulii are in the ratio of 2:3. They are suspended and loaded with the same mass. When stretched and released, they will oscillate with time periods in the ratio of

A
3:2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3 : 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
33:22
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
9 : 4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 3:2

Young modulus Y=(F/A)l/L=FLlA where l is the extension of spring of original length L and A be the cross-sectional area and F=mg , force applied.

now force constant k=Fl=AYL
Time period T=2πmk=2πmLAY
thus, T1T2=Y2Y1=32


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Law of Conservation of Energy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon