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Standard XII

Physics

Bernoulli's Principle

Two springes ...

Question

Two springes of different cross-sections (without needles) filled with water are connected with a tightly fitted rubber tube filled with water.Diameters of the smaller piston and larger piston are 1.0 cm and 3.0 cm respectively.Find the force exerted on the larger piston when a force of 10 N is applied to the smaller piston.

90 N

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40 N

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50 N

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80 N

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Solution

The correct option is A 90 N
$\begin{matrix} \frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} \Rightarrow \frac{10}{π {(\frac{1}{2})}^{2}} = \frac{F_{2}}{π {(\frac{3}{2})}^{2}} \Rightarrow 90 = F_{2} ∴ F_{2} = 90 N H e n c e, o p t i o n A i s c o r r e c t a n s w e r . \end{matrix}$

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The correct option is A 90 NF1A1=F2A2⇒10π(12)2=F2π(32)2⇒90=F2∴F2=90NHence,optionAiscorrectanswer.

The correct option is A 90 N
$\begin{matrix} \frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} \Rightarrow \frac{10}{π {(\frac{1}{2})}^{2}} = \frac{F_{2}}{π {(\frac{3}{2})}^{2}} \Rightarrow 90 = F_{2} ∴ F_{2} = 90 N H e n c e, o p t i o n A i s c o r r e c t a n s w e r . \end{matrix}$