Two springs A and B ( $k_{A}$ = 2 $k_{B}$ ) are stretched by applying forces of equal magnitudes at the four ends. If the energy stored in A is E, that in B is

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Two springs A and B having spring constant KA and KB (KA= 2KB) are stretched by applying force of equal magnitude. If energy stored in spring A is E then energy stored in B will be :

The correct option is A 2EAs, E= 1/2 × k × x^2 =1/2 × (kx)^2 × 1/k = 1/2 × F^2 ×1/k Keeping F constant, E is inversely proportional to k. Therefore as k becomes half so enegy doubles. Hence 2E.

Two springs A and B having spring constant $K_{A}$ and $K_{B}$ ( $K_{A}$ = $2 K_{B}$ ) are stretched by applying force of equal magnitude. If energy stored in spring A is E then energy stored in B will be :

The correct option is A 2E
As, E= 1/2 × k × x^2 =1/2 × (kx)^2 × 1/k = 1/2 × F^2 ×1/k Keeping F constant, E is inversely proportional to k. Therefore as k becomes half so enegy doubles. Hence 2E.