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Work Energy Theorem

Two springs A...

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Two springs A and B having spring constant KA and KB (KA = 2KB) are stretched by applying force of equal magnitude. If energy stored in spring A is EA then energy stored in B will be

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Q. Two springs A and B having spring constant

K_{A}

K_{B}

K_{A} = 2 K_{B}

) are stretched by applying force of equal magnitude. If energy stored in spring A is

E_{A}

then energy stored in B will be

Q. Two springs have force constants

k_{A}

k_{B}

k_{B} = 2 k_{A}

. The four ends of the springs are stretched by the same force. If energy stored in spring A is

E

, then energy stored in spring B is

A

B

are stretched by applying forces of equal magnitudes. If the energy stored in

A

is E, then the energy stored in B will be-
(Given relation between spring constants of

A

B

(k_{A} = 2 k_{B})

)

A

B

(K_{A} = 2 K_{B})

are stretched by applying force of equal magnitudes at the four ends.If the energy stored in

A

E

B

Q. Two springs A and B (

k_{A} = 2 k_{B}

) are stretched by applying forces of equal magnitudes at the four ends. If the energy stored in A is E, then in B is (assume equilibrium):

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