Two springs A and B with same spring constant 'k' are compressed to different lengths $x m e t r e s$ and $3 x m e t r e s$ respectively. The forces developed in A and B are in the ratio:

4:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
1:3

Force in spring = $- k x$ ( minus represents force is always opposite to displacement of spring)

Force in spring 'A' = $- k x$

Force in spring 'B' = $- 3 k x$

Force in 'A' : Force in 'B' = 1:3

Suggest Corrections

Similar questions

Two springs of spring constants 1500 N/mand 3000 N/mrespectively are stretched with the same force. The ratio of potential energies will be

There are two mass less spring A and B of spring constant $K_{A}$ and $K_{B}$ respectively $K_{A} > K_{B}$ . If $W_{A} a n d W_{B}$ be denoted as work done on A andwork done on B respectively, then

Q. There are two massless springs A and B of spring constant

K_{A}

and

K_{B}

respectively and

K_{A} > K_{B}

. If

W_{A}

and

W_{B}

be denoted as work done on A and work done on B respectively, then

Q. There are two mass less spring A and B of spring constant

K_{A}

and

K_{B}

respectively and

K_{A} > K_{B}

. If

W_{A}

and

W_{B}

be denoted as work done on A and work done on B respectively, then

Two springs of spring constants 1500 N/m and 3000 N/m respectively are stretched with the same force. They will have potential energy in the ratio

Join BYJU'S Learning Program

Two springs A and B with same spring constant 'k' are compressed to different lengths x metres and 3x metres respectively. The forces developed in A and B are in the ratio:

The correct option is B 1:3 Force in spring = −k x ( minus represents force is always opposite to displacement of spring) Force in spring 'A' = −k x Force in spring 'B' = −3 k x Force in 'A' : Force in 'B' = 1:3

Two springs A and B with same spring constant 'k' are compressed to different lengths $x m e t r e s$ and $3 x m e t r e s$ respectively. The forces developed in A and B are in the ratio:

The correct option is B
1:3

Force in spring = $- k x$ ( minus represents force is always opposite to displacement of spring)

Force in spring 'A' = $- k x$

Force in spring 'B' = $- 3 k x$

Force in 'A' : Force in 'B' = 1:3