Two springs have their force constant as k 1 and k 2 k 1- k 2- When they are stretched by the same forceA- More work is done in case of second springB- Equal work is done in case of both the springsC- No work is done in case of both the springsD- More work is done in case of first spring

W = F^2/2k If both springs are strectched by same force then W ∞1/k As k_1 gt; k_2 therefore W_1 lt; W_2 i.e. more work is done in case of second sprin ...

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Standard XII

Physics

Work Done: Spring

Two springs h...

Question

Two springs have their force constant as $k_{1}$ and $k_{2} (k_{1} > k_{2})$ . When they are stretched by the same force

No work is done in case of both the springs

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Equal work is done in case of both the springs

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More work is done in case of second spring

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More work is done in case of first spring

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Solution

The correct option is C
More work is done in case of second spring

$W = \frac{F^{2}}{2 k}$

If both springs are strectched by same force then $W \infty \frac{1}{k}$

As $k_{1} > k_{2}$ therefore $W_{1} < W_{2}$

i.e. more work is done in case of second spring.

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