Two springs of force constant $k$ and $2 k$ are connected to a mass as shown below : The frequency of oscillation of the mass is

(1 / 2 π) \sqrt{(k / m)}

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(1 / 2 π) \sqrt{(2 k / m)}

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(1 / 2 π) \sqrt{(3 k / m)}

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(1 / 2 π) \sqrt{(m / k)}

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Solution

The correct option is C $(1 / 2 π) \sqrt{(3 k / m)}$
For any spring-mass system time period of oscillation,
$T = 2 π \sqrt{\frac{m}{k}} \Rightarrow n = \frac{1}{2 π} \sqrt{\frac{k}{m}}$
In the present case total spring constt.
$= k + 2 k = 3 k$
$n = \frac{1}{2 π} \sqrt{\frac{3 k}{m}}$

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Two springs of force constant k and 2k are connected to a mass as shown below : The frequency of oscillation of the mass is

The correct option is C (1/2π)√(3k/m)For any spring-mass system time period of oscillation,T=2π√mk⇒n=12π√kmIn the present case total spring constt.=k+2k=3kn=12π√3km

Two springs of force constant $k$ and $2 k$ are connected to a mass as shown below : The frequency of oscillation of the mass is

The correct option is C $(1 / 2 π) \sqrt{(3 k / m)}$
For any spring-mass system time period of oscillation,
$T = 2 π \sqrt{\frac{m}{k}} \Rightarrow n = \frac{1}{2 π} \sqrt{\frac{k}{m}}$
In the present case total spring constt.
$= k + 2 k = 3 k$
$n = \frac{1}{2 π} \sqrt{\frac{3 k}{m}}$