Question

Two springs of spring constants $1000N/m$ and $2000N/m$ are stretched with same source. They will have potential energy in the ratio of

• A. $1:2$
  
• B. $1:4$
  
• C. $2:1$
  
• D. $4:1$
  

Answer 1

The correct option is C $2:1$

The energy of spring is given by $PE=\frac{1}{2}\ast k\ast x^2$

Therefore when stretch is same the x is same hence formula reduce to ratio of PE and k

$\frac{P{E}_1}{P{E}_2}=\frac{k_1}{k_2}$

$\frac{P{E}_1}{P{E}_2}=\frac{2000}{1000}=2:1$