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Question

Two springs of spring constants k1 and k2are joined in series. The effective spring constant of the combination is given by -
69343_28f84e12e9044cddb8bf6d3bc5947afa.png

A
(k1+k2)2
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B
k1+k2
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C
k1k2(k1+k2)
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D
k1k2
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Solution

The correct option is C k1k2(k1+k2)
Two springs of spring constant k1 and k2 are joined in series.
The effective spring constant of the combination is -
We know using hooke's law
f1k1=x1f2k2=x2X=f1k1+f2k2X=Fk1+Fk2X=F(1k1+1k2)X=F[(k1+k2)k1k2]F=k1k2(k1+k2)XTherefore,k=k1k2(k1+k2)

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