Two squares of area 9 m 2 are placed adjacent to each other- what would be dimensions of the new rectangle formed-A- Length -6 m- breadth -3 mB- Length -6 m- breadth -6 mC- Length -3 m- breadth -3 mD- Length -18 m- breadth -6 m

The correct option is The area of the square = 9 m^2 Area of square = side × side = side^2 = 9 = 3 × 3 = 3^2 side = 3 m Consider, the square of side 3 ...

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Standard VI

Mathematics

Calculating Fractional Area

Two squares o...

Question

Two squares of area $9 m^{2}$ are placed adjacent to each other, what would be dimensions of the new rectangle formed ?

Length = 6 m, breadth = 3 m

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Length = 3 m, breadth = 3 m

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Length = 6 m, breadth = 6 m

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Length = 18 m, breadth = 6m

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Solution

The area of the square = $9 m^{2}$

$A r e a o f s q u a r e = s i d e \times s i d e = s i d e^{2} = 9 = 3 \times 3 = 3^{2}$

side = 3 m

Consider, the square of side 3 m

When we place two square adjacent to each other it will form a rectangle

The sides of the rectangle will be , Length = 3 + 3 = 6 m and breadth = 3 m

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Two squares of area 9m2 are placed adjacent to each other, what would be dimensions of the new rectangle formed ?

The area of the square = 9m2 Area of square =side × side=side2=9=3×3=32 side = 3 m Consider, the square of side 3 m When we place two square adjacent to each other it will form a rectangle The sides of the rectangle will be , Length = 3 + 3 = 6 m and breadth = 3 m

Two squares of area $9 m^{2}$ are placed adjacent to each other, what would be dimensions of the new rectangle formed ?