Two squares of side $9 c m$ attached together.Find the perimeter of the resulting figure.

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Solution

Two squares of side $9 c m$ are attached together to form a rectangle of length $9 + 9 = 18 c m$
And the width remains same
So the perimeter is $2 (l + b) = 2 (18 + 9) = 2 (27) = 54 c m$

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Two squares of side 9cm attached together.Find the perimeter of the resulting figure.

Two squares of side 9cm are attached together to form a rectangle of length 9+9=18cmAnd the width remains same So the perimeter is 2(l+b)=2(18+9)=2(27)=54cm

Two squares of side $9 c m$ attached together.Find the perimeter of the resulting figure.

Two squares of side $9 c m$ are attached together to form a rectangle of length $9 + 9 = 18 c m$
And the width remains same
So the perimeter is $2 (l + b) = 2 (18 + 9) = 2 (27) = 54 c m$