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Byju's Answer

Standard XI

Mathematics

Negation

Two statement...

Question

Two statements p and q are given below

p: It is snowing
q: I am cold

The compound statement "It is snowing and it is not that I am cold" is given by

$p \land \sim q$

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$p \land q$

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$\sim p \land q$

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$\sim p \lor \sim q$

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Solution

The correct option is A
$p \land \sim q$

p: It is snowing
q: I am cold
~q: It is not that I am cold

Then the given statement is $p \land \sim q$

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Similar questions

Q. If

p :

It is snowing,

q :

I am cold, then the compound statement "It is snowing and it is not that I am cold" is given by :

Q. Let

p \equiv

"It snows today",

q \equiv

"Roads will not be filled with snow." and

r \equiv

"There might be a traffic jam."
What can be concluded from "If it is snowing today then roads will be filled with snow and there might be a traffic jam."

Q. Let

P

and

Q

be two matrices different from identity matrix

I

and null matrix

O

such that

P Q = Q P

and if

P^{6} - Q^{6} = P^{5} - Q^{5} = P^{4} - Q^{4} = I

then,

p :

I am topper.

q :

I worked hard.

The symbolic form of the statement : "I am topper or I worked hard", formed from statements

p, q

can be

Q. If the symbols have been assigned the meaning as given below:

P @ Q

\to

P is greater than Q

Q

\rightarrow$ P is either greater or equal to Q

P & Q

\to

P is smaller than Q

⋆

\to

P is either smaller than or equal to Q

P = Q

\to

P is equal to Q

Now assuming the given statements to be true, find which of the two conclusions I and II given below them is / are definitely true? Give answer.

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Two statements p and q are given below p: It is snowing q: I am cold The compound statement "It is snowing and it is not that I am cold" is given by

The correct option is A p ∧∼q p: It is snowing q: I am cold ~q: It is not that I am cold Then the given statement is p ∧∼q

Two statements p and q are given below

p: It is snowing
q: I am cold

The compound statement "It is snowing and it is not that I am cold" is given by

The correct option is A
$p \land \sim q$

p: It is snowing
q: I am cold
~q: It is not that I am cold

Then the given statement is $p \land \sim q$