Two steel columns P (Length L and yield strength fy=250 MPa) and Q (length 2L and yield strength fy=500 MPa) have the same cross-sections and end-conditions. The ratio of buckling load of column P to that of column Q is:
A
0.5
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B
1.0
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C
2.0
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D
4.0
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Solution
The correct option is D 4.0 Buckling load as per Euler's method is =π2EIL2
As no information regarding cross-sectional area is given, ratio of buckling load ⇒PPPQ=(L2QL2P)=(2LL)2=4