Question

Two steel shafts A and B are used for transmitting power. The ratio of revolutions of shafts i.e., $\frac{N_A}{N_B}=2.$ The ratio of torques on shafts i.e., $\frac{T_A}{T_B}=\frac{1}{2}$. The ratio of the horse power transmitted by the shafts i.e. $\frac{P_A}{P_B}$ would be

• A. 1/2
• B. 1/4
• C. 1
• D. 2

Answer 1

The correct option is C 1

$P=\frac{2\pi NT}{60}$

$\therefore \frac{P_A}{P_B}=\frac{N_A}{N_B}\times \frac{T_A}{T_B}=1.0$