Two stone are projected with the same speed but making diffrent angles with the horizontal. Their ranges are equal. If the angle of projection of one is π3 and its maximum height is y1 then the maximum height of the other will be:
ranges of both projectile motion are equal therefore
R1=R2
v2osin2θ1g=v2osin2θ2g
sin2θ1=sin2θ2 --------------(i)
⇒θ1+θ2=π2
⇒θ2=π6
maximum height of first projectile at angle π3 is y1
y1=v2osin2θ12g
y1=v2osin2π32g=3v2o8g
y2=v2osinθ22g=v20sin3002g=v208g
∴y2=y13