Two stones are dropped from the top of a tower at half a second apart. The time after dropping the first stone at which the distance between the two stones is 20 m is (g=10ms−2)
If the first stone travels for t sec then the second stone travels for (t -0.5) sec.
h1=5t2 ___(1) g=10
h2=5[t−12]2
20=h2=5[t−12]2____(2)
on solving we get (1) and (2) we get
t=4.25sec.