Question

Two stones are projected with the same magnitude of velocity, but making different angles with horizontal. The angle of projection of one is $\frac{\pi }{3}$ and its maximum height is Y, the maximum height attained by the other stone with as $\frac{\pi }{6}$ angle of projection is

• A. Y
• B. 2 Y
• C. 3 Y
• D.

Answer 1

The correct option is D

When two stones are projected with same velocity then for complementary angles$\theta$ and ${90}^{\circ }-\theta$
Ratio of maximum heights : $\frac{H_1}{H_2}=ta{n}^2\theta =ta{n}^2\frac{\pi }{3}=3\Rightarrow H_2=\frac{Y}{3}$