Two stones are thrown up simultaneously with initial speeds of $u_{1} a n d u_{2} (u_{2} > u_{1}) .$ They hit the ground after 6 s and 10 s respectively. Which graph in figure correctly represents the time variation of $Δ x = (x_{2} - x_{1}),$ the relative position of the second stone with respect to the first upto t = 10 s?
Assume that the stones do not rebound after hitting the ground.

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Solution

The correct option is A
Initially relative acceleration between them is zero, so distance between them will increase linearly. Later when one stone strikes the ground, relative acceleration is g so distance will decrease parabolically.

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Similar questions

Q. Two stones are thrown up simultaneously with initial speeds

u_{1}

and

u_{2} (u_{2} > u_{1})

. They hit the ground after

6 s

and

10 s

respectively. Which graph correctly represents the time variation of,

Δ x = (x_{2} - x_{1})

, the relative position of the second stone with respect to the first upto

t = 10 s

?
Assume that the stones do not rebound after hitting the ground.

Two stones are thrown up simultaneously with initial speeds of $u_{1}$ and $u_{2} (u_{2} > u_{1})$ . They hit the ground after 6 s and 10 s respectively. Which of the following graphs correctly represents the time variation of $Δ x = (x_{2} - x_{1})$ , the relative position of the second stone with respect to the first till t = 10 s? Assume that the stones do not rebound after hitting the ground.