Two stones are thrown vertically upward simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them would be in the ratio of u1²:u2².

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Question 24
Two stones are thrown vertically upwards simultaneously with their initial velocities $u_{1}$ and $u_{2}$ respectively. Prove that the heights reached by them would be in the ration of $u_{1}^{2}$ ; $u_{2}^{2}$ ( Assume upward acceleration is –g and downward acceleration to be +g).

Q. Two stones are thrown vertically upwards simultaneously with their initial velocities

u_{1}

and

u_{2}

respectively. The heights reached by them would be in the ratio of

Q. Two stones are thrown vertically upwards simultaneously with their initial velocities

u_{1}

and

u_{2}

respectively. What is ratio of the heights reached by them (Assume acceleration is g downwards)?

Two bodies are thrown vertically upwards with their initial speeds in the ratio 2:3 . The ratio of the maximum heights reached by them and the ratio of their time taken by them to return back to the ground respectively are ___________________.(with explain)

Q. Two stones are dropped down simultaneously from different heights with initial speed

u_{1} = 0

and

u_{2} = 30 m/s

respectively. If the initial distance between them is

10 m

and mass of the first stone is twice that of the second stone, find the velocity of their

C O M

after

2 s

. [Take

g = 10 {m/s}^{2}

]

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